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#1
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Hi,
Right before exercise 1.10, the book states, "The next exercise considers a simple coin experiment that further illustrates the difference between a fixed h and the final hypothesis g selected by the learning algorithm". That statement confuses me a bit because: 1. I don't really see any function (no target function f and no hypothesis h) but the real probability of getting head of a fair coin. No? 2. Cmin illustrates that "if the sample was not randomly selected but picked in a particular way, we would lose the benefit of the probabilistic analysis (Hoeffding Inequality?)" (quoted from page 20). No? Last question, although Cmin is picked in a particular way, if we treat each v from each 10 flips of each coin in each trial from one unique bin (such that the v's from 10 flips from the same coin in 2 different trials come from 2 bins). Then, we can still apply non vanilla version Hoeffding Inequality --P[|Ein(g)-Eout(g)| > ε] <= 2M*e^-2N*(ε^2). Hope I can get some clarification. Thanks! |
#2
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Small modification to #1:
1. I don't really see any function (no target function f and no hypothesis h) but the *expected* probability of getting head of a fair coin. No? |
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