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Old 10-20-2012, 08:43 AM
weiss weiss is offline
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Default Definition "n choose k"

How do you define "n choose k" for k > n?

I learned in all my courses that this expression is not defined, but since I lost points in the questions 7 and 10, I think you are following another definition in this case.
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Old 10-20-2012, 10:19 AM
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yaser yaser is offline
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Default Re: Definition "n choose k"

Quote:
Originally Posted by weiss View Post
How do you define "n choose k" for k > n?
It is defined as zero based on the combinatorial interpretation "the number of ways you can choose k objects from n distinct objects," which is none if k>n.
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