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Old 04-29-2013, 01:24 PM
a.sanyal902 a.sanyal902 is offline
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Default Lecture 6- 2N sample

Hi all,
At the end of lecture 6, Prof. Yaser replaces one sample with 2 samples of size N each. We then replace m(N) with m(2N) in the inequality.

However, these are 2 distinct samples. So won't the maximum no. of hypothesis actually be 2m(N), which in general is more than m(2N)) ?
The constraints of 2N points would hold if it were a single sample set, but here more no. of hypothesis are possible as the N-sets are distinct.

Is this the reason for the additional factors in the inequality?
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Old 04-29-2013, 02:45 PM
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yaser yaser is offline
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Default Re: Lecture 6- 2N sample

Quote:
Originally Posted by a.sanyal902 View Post
Hi all,
At the end of lecture 6, Prof. Yaser replaces one sample with 2 samples of size N each. We then replace m(N) with m(2N) in the inequality.

However, these are 2 distinct samples. So won't the maximum no. of hypothesis actually be 2m(N), which in general is more than m(2N))?
I am not sure I completely got the point that you are making, so let me just address the above statement. The growth function normally grows very fast, so it will more than double in value when its argument doubles. When we consider all dichotomies on 2N points, whether we view them as one sample or two samples, the number to be considered is m(2N).
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Old 04-29-2013, 10:22 PM
a.sanyal902 a.sanyal902 is offline
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Default Re: Lecture 6- 2N sample

Thank you Prof! I was a little confused earlier. Much clearer now!
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