
#1




Question on Lecture 2
Hi,
In reviewing some of the lectures, I have a question about Lecture 2 (slide 14; ~ 47 minute mark), "Coin analogy", how was 63% arrived at as the answer to the second question: If you toss 1000 fair coins 10 times each, what is the probability that some coin will get 10 heads? Thanks, Paul 
#2




Re: Question on Lecture 2
Quote:
Therefore, for each coin, the probability of not getting 10 heads is 1 minus that, approximately 0.999 The probability that none of the 1000 coins gets 10 heads is that to the power 1000, and we approximate by since the limit of is . Finally, the probability that at least one coin will get 10 heads is one minus that, which is and this is approximately 0.63. PS: You can quote any part of the video lecture by using the lecture tags, in this case [lecture2] tag, as explained in the sticky thread about including a video segment.
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Where everyone thinks alike, no one thinks very much 
#3




Re: Question on Lecture 2
Thanks Prof. Yaser and also for reminding me to use the post tags!

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