
#1




Noisy Targets as deterministic target function
Hi everyone,
As I understood, noisy target is when we observe that for a same value of x we get different values of y. Then, we model this function as a distribution P(yx) (instead of a deterministic one) But later on in the book, Yaser says: "This view suggests that a deterministic target function can be considered a special case of a noisy target, just with zero noise. Indeed, we can formally express any function f as a distribution P(yx) by choosing P(yx) to be zero for all y except y = f(x)". My question is: How we can consider a value of y is equal to f(x), since the function f is a distribution. Suppose we have two different values of y for the same input x, what of these two y's is different to f(x)? 
#2




Re: Noisy Targets as deterministic target function
Quote:
The case you mention, where there are two possible 's for the same is a case of a noisy target, not a deterministic target.
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#3




Re: Noisy Targets as deterministic target function
It is clear now. Thanks a lot!

Tags 
chapter 1, noisy target 
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