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Old 08-22-2015, 01:50 PM
Rotimi Rotimi is offline
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Join Date: Aug 2015
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Default Problem 1.1

I could not use Bayes' theorem to solve Problem 1.1 but I thought of an 'alternative' method which gave me the answer 2/3. I want to know if this method is right or not. It's as follows:

Since there are 2 black balls and 1 white ball left are choosing the first black ball, the chances that the second ball is black is 2/3 since there are 3 balls left.

Is this method right or not?
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