LFD Book Forum  

Go Back   LFD Book Forum > Course Discussions > Online LFD course > Homework 4

Reply
 
Thread Tools Display Modes
  #1  
Old 04-30-2012, 10:29 AM
stordoff stordoff is offline
Junior Member
 
Join Date: Apr 2012
Posts: 2
Default HW4, Question 1

For the VC bound, we have a m_H(2N) term. Should this be replaced with (2N)^dvc, or merely N^dvc?

I presume the former, but both give answers around 400,000-500,000, so confirmation would be useful.
Reply With Quote
  #2  
Old 04-30-2012, 10:51 AM
sakumar sakumar is offline
Member
 
Join Date: Apr 2012
Posts: 40
Default Re: HW4, Question 1

Quote:
Originally Posted by stordoff View Post
For the VC bound, we have a m_H(2N) term. Should this be replaced with (2N)^dvc, or merely N^dvc?

I presume the former, but both give answers around 400,000-500,000, so confirmation would be useful.
The VC Generalization bound is defined in terms of m_H(2N), so that's what I used. Specifically m_H(2N) <= (2N)^dvc + 1, so I substituted the Right hand term for m_H(2N).
Reply With Quote
  #3  
Old 04-30-2012, 03:01 PM
rodrigo rodrigo is offline
Member
 
Join Date: Apr 2012
Location: London
Posts: 20
Default Re: HW4, Question 1

I used the bound we derived in lecture 6: sum(i=0 to dvc, of N choose i ). This should yield a tighter bound on e as sum(i=0 to dvc of, N choose i ) <= (2N)^dvc
Reply With Quote
  #4  
Old 04-30-2012, 03:38 PM
yaser's Avatar
yaser yaser is offline
Caltech
 
Join Date: Aug 2009
Location: Pasadena, California, USA
Posts: 1,477
Default Re: HW4, Question 1

Quote:
Originally Posted by rodrigo View Post
I used the bound we derived in lecture 6: sum(i=0 to dvc, of N choose i ). This should yield a tighter bound on e as sum(i=0 to dvc of, N choose i ) <= (2N)^dvc
I take it you used {2N \choose i} since you are evaluating the growth function at 2N.
__________________
Where everyone thinks alike, no one thinks very much
Reply With Quote
  #5  
Old 04-30-2012, 05:45 PM
rodrigo rodrigo is offline
Member
 
Join Date: Apr 2012
Location: London
Posts: 20
Default Re: HW4, Question 1

Quote:
Originally Posted by yaser View Post
I take it you used {2N \choose i} since you are evaluating the growth function at 2N.
Yes indeed! On my previous post I was referring to how one can substitute mH(N), as shown on lecture 6. But reading through the thread again I can see how that may have been misleading given the context.

Thanks professor.
Reply With Quote
Reply

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT -7. The time now is 05:00 PM.


Powered by vBulletin® Version 3.8.3
Copyright ©2000 - 2019, Jelsoft Enterprises Ltd.
The contents of this forum are to be used ONLY by readers of the Learning From Data book by Yaser S. Abu-Mostafa, Malik Magdon-Ismail, and Hsuan-Tien Lin, and participants in the Learning From Data MOOC by Yaser S. Abu-Mostafa. No part of these contents is to be communicated or made accessible to ANY other person or entity.