#11




Re: Problem 1.9
Quick question on Part D...
I agree that s = ln(a / (1a)) is the value of s that minimizes e^(sa)U(s), where I'm using "a" to represent "alpha." I think that, if you plug this value of s in, you get 2^(b), where I'm using "b" to represent "beta." So, 2^(b) < e^(sa)U(s), by definition of minimization. Then, raising to the power of N, we get: 2^(bN) < (e^(sa)U(s))^N, but this inequality is the wrong way. Any tips? 
#12




Re: Problem 1.9
Ah, maybe it's because the inequality holds for any s, it must hold for the min.

#13




Re: Problem 1.9
You got it. :)
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