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  #31  
Old 04-23-2018, 08:00 AM
samyar1 samyar1 is offline
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Default Re: Discussion of the VC proof

thank you for your answer. i like it.
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  #32  
Old 05-02-2018, 09:08 PM
ebookrally ebookrally is offline
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Default Re: Discussion of the VC proof

Quote:
Originally Posted by magdon View Post
You are correct. We could have made other assumptions.

But there is a special reason why we DO want 1. Because we are bounding the probability, and so there is nothing to prove if we claim that a probability is less equal to 1. So, whenever the RHS (i.e. the bound) evaluates to 1 or bigger, there is nothing to prove. So we only need to consider the case when the bound evaluates to less than 1.
i had same question but thanks to your website my question just solved. thanks
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  #33  
Old 05-02-2018, 09:16 PM
iranpaper iranpaper is offline
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Default Re: Discussion of the VC proof

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Originally Posted by yaser View Post
Here is what it means. Let's say that you have P(A|B)\le \alpha for every B. Then, regardless of what the probability distribution of B, it will be true that P(A)\le \alpha since we can multiply both sides of P(A|B)\le \alpha by P(B) and integrate B out.
thank you for your answer.
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