Definition "n choose k"

[weiss]

How do you define "n choose k" for k > n?

I learned in all my courses that this expression is not defined, but since I lost points in the questions 7 and 10, I think you are following another definition in this case.

[yaser]

Originally Posted by weiss

How do you define "n choose k" for k > n?

It is defined as zero based on the combinatorial interpretation "the number of ways you can choose objects from distinct objects," which is none if .