 LFD Book Forum *ANSWER* Hw 2, problem 3

#1
 useral Member Join Date: Apr 2012 Posts: 22 *ANSWER* Hw 2, problem 3

Hello,

I must be missing the forest for the trees, but I was thinking that the answer should be the weighted sum of the probabilities of (y = f(x)) and (y =/= f(x)), and the weight mu (corresponding to an error, i.e. y =/= f(x)) should be assigned to the probability of that error, i.e. to 1-lambda.

This reasoning gives the answer [d]. Is it flawed?
#2 htlin NTU Join Date: Aug 2009 Location: Taipei, Taiwan Posts: 601 Re: Hw 2, problem 3

Quote:
 Originally Posted by useral Hello, I must be missing the forest for the trees, but I was thinking that the answer should be the weighted sum of the probabilities of (y = f(x)) and (y =/= f(x)), and the weight mu (corresponding to an error, i.e. y =/= f(x)) should be assigned to the probability of that error, i.e. to 1-lambda. This reasoning gives the answer [d]. Is it flawed?
The cases that would be different from is when either, but not both, of these events happen: , or . Hope this helps.
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#3
 useral Member Join Date: Apr 2012 Posts: 22 Re: Hw 2, problem 3

Quote:
 Originally Posted by htlin The cases that would be different from is when either, but not both, of these events happen: , or . Hope this helps.
Thanks, that clarifies it.

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