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  #11  
Old 06-23-2017, 03:42 PM
RicLouRiv RicLouRiv is offline
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Default Re: Problem 1.9

Quick question on Part D...

I agree that s = ln(a / (1-a)) is the value of s that minimizes e^(-sa)U(s), where I'm using "a" to represent "alpha."

I think that, if you plug this value of s in, you get 2^(-b), where I'm using "b" to represent "beta."

So, 2^(-b) < e^(-sa)U(s), by definition of minimization.

Then, raising to the power of N, we get:

2^(-bN) < (e^(-sa)U(s))^N, but this inequality is the wrong way.

Any tips?
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  #12  
Old 06-24-2017, 08:36 AM
RicLouRiv RicLouRiv is offline
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Default Re: Problem 1.9

Ah, maybe it's because the inequality holds for any s, it must hold for the min.
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  #13  
Old 06-29-2017, 09:00 PM
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htlin htlin is offline
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Default Re: Problem 1.9

Quote:
Originally Posted by RicLouRiv View Post
Ah, maybe it's because the inequality holds for any s, it must hold for the min.
You got it. :-)
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