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Old 10-23-2014, 01:52 PM
AnonymousMachine AnonymousMachine is offline
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Default Problem 4.26
Can someone confirm if A^-1(\lambda) is equivalent to A(\lambda)^-1 ?
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Old 10-24-2014, 11:57 PM
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htlin htlin is offline
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Default Re: Problem 4.26
In this context, yes. Thank you for pointing out the inconsistency.
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