#1




Question 6 Target functions to consider = 8
I'm still confused why there are only 8 target functions we need to consider since there are only 3 points within X but outside of D? Why are the possible target functions we need to consider 8 then?
Is it because the remaining 3 input vectors have 8 possible ways the corresponding y(n) values could be assigned and thus each different one that is a target function? 
#2




Re: Question 6 Target functions to consider = 8
Sounds reasonable. :)
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#3




Re: Question 6 Target functions to consider = 8
Thanks!

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