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#1
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I am having a hard time finding a good way to visualize this. Maybe someone can make suggestions.
One thing I decided early on: A "best" set of N points (with a maximal number of dichotomies) has to be convex. If it is concave, make the point on the inside -1 and three points surrounding it +1 and it won't work. Once the set is convex (maybe you can put them on a circle WLOG or some such), I _think_ I can guess the number that will force no breaking, but I don't have a clear argument. |
#2
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![]() Quote:
http://book.caltech.edu/bookforum/showthread.php?t=2606 and we can discuss this further.
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Where everyone thinks alike, no one thinks very much |
#3
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Well, I see that an N-gon (won't say which) is easy to shatter, and the (N+2)-gon is easy to see that it can't be shattered. So I know which of the answers to choose, but I'm still not clear on the (N+1)-gon in between.
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#4
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I took out the *ANSWER* warning since the discussion seems safe so far.
__________________
Where everyone thinks alike, no one thinks very much |
#5
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Ah, well, I guess an (N+1)-gon works too - brute force check on all triangles. Not very elegant, but it works.
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#6
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I was having about the same troubles figuring out the perceptron problem, but I think looking in the book (*ANSWER*) helps a lot.
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