#1




*ANSWER* checking the answer of Q1
Dear all,
For Q1, I got nu_min around 0.375. Therefore, [d] would be the closet answer. I feel the answer is reasonable, for the following consideration: 1. The probablity of getting no head outcomes in 10 trails is 1/1024. 2. For 1000 tentimesthrown coins, the probability of getting no one with head count = 0 is [(10241)/1024]^1000 = 0.375. 3. In most cases, when there is no one with head count =0, the lowest head count is most likely to be 1. 4. Therefore, the expectation value of nu_min will be approximately 0*0.625 + 1*0.375 = 0.375. Am I doing anything wrong? Or I misunderstood the question? 
#2




Re: *ANSWER* checking the answer of Q1
Quote:
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#3




Re: *ANSWER* checking the answer of Q1
Hi Yaser,
I see. nu is the fraction, not the number of the head count. Thank you! 
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