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Old 02-16-2016, 07:29 PM
wordchao wordchao is offline
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Join Date: Feb 2016
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Default example non-overlap hypothesis set H to make union bound equals vc bound

consider the union bound, when H consists of only h1 and h2,
<=Pr[|Ein(h1)-Eout(h1)|>e or |Ein(h2)-Eout(h2)|>e] (eq.1)
<=Pr[|Ein(h1)-Eout(h1)|>e] + Pr[|Ein(h2)-Eout(h2)|>e] (eq.2)
=2exp(-2Ne^2) (eq.3)

i wonder which kind of h1 and h2 can more "accurately" satisfy the union bound, maybe this means union bound equals vc bound.
in other words, can i find h1 and h2 to let (eq.1)=(eq.2)?

Pr[|Ein(h1)-Eout(h1)|>e or |Ein(h2)-Eout(h2)|>e]
=Pr[|Ein(h1)-Eout(h1)|>e and |Ein(h2)-Eout(h2)|>e] (eq.a)
+Pr[|Ein(h1)-Eout(h1)|>e and |Ein(h2)-Eout(h2)|<=e] (eq.b)
+Pr[|Ein(h1)-Eout(h1)|<=e and |Ein(h2)-Eout(h2)|>e] (eq.c)

if (eq.2)=(eq.1), then,

but i cannot find the example h1&h2, which means h1 and h2 has no overlap when considering the union bound.
can u help? thanks.
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hypothesis, on-overlap, union bound

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