Quote:
Originally Posted by kkkkk
I believe there are other possible solutions. So long that for any 2 of the 3 columns, if there are less than 2^N = 4 unique patterns, the break point of 2 is satisifed.
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I agree.
But in the lecture Prof. Abu-Mostafa seemed to prompt the class, asking if each successive dichotomy (composed from counting to 8 in binary) were allowed or not allowed, as if the answer were unique.