View Single Post
  #12  
Old 11-04-2014, 08:24 PM
jokovc jokovc is offline
Junior Member
 
Join Date: Nov 2014
Posts: 2
Default Re: Discussion of the VC proof

Quote:
Originally Posted by yaser View Post
Here is what it means. Let's say that you have P(A|B)\le \alpha for every B. Then, regardless of what the probability distribution of B, it will be true that P(A)\le \alpha since we can multiply both sides of P(A|B)\le \alpha by P(B) and integrate B out.
I think this is so much clearer than when it is put in sentences. Thank you.
Reply With Quote