Thread: Q4) h(x) = ax
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Old 01-31-2013, 11:16 AM
geekoftheweek geekoftheweek is offline
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Default Re: Q4) h(x) = ax

Is there a best way to minimize the mean-squared error? I am doing gradient descent with a very low learning rate (0.00001) and my solution is diverging! not converging. Is it not feasible to do gradient descent with two points when approximating a sine?
Thanks
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