View Single Post
  #2  
Old 08-10-2014, 07:49 PM
yaser's Avatar
yaser yaser is offline
Caltech
 
Join Date: Aug 2009
Location: Pasadena, California, USA
Posts: 1,477
Default Re: Question on HW2.1

Quote:
Originally Posted by yusunchina View Post
P(#heads_min = i) = 1000 * P( one gets i intersect the others get >= i)
This formula assumes that the events "one gets i intersect the others get >= i" (with the "one" fixed at one coin at a time) are disjoint, otherwise this would be an over-count. These events are in fact overlapping. For instance, the case where all the coins get exactly i (which is admittedly an extremely unlikely event but chosen here as a simple illustration) would be counted in all 1000 cases, although it happens only "once."
__________________
Where everyone thinks alike, no one thinks very much
Reply With Quote