Thread: Question 11
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Old 06-10-2013, 07:30 PM
jforbes jforbes is offline
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Join Date: Apr 2013
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Default Re: Question 12

It seems like the original question was never answered.

Geometrically, one can find a w1, w2, and b which define the separating plane. Clearly you get the same plane if you multiply w1, w2, and b by some constant A. In the SVM formalism A was fixed so that w.z+b=1 at the nearest positive point.

Do we need to
-choose the w1, w2, and b which define the correct plane AND have the correct A, or
-is it sufficient to choose one of the infinitely many w1, w2, and b which define the correct plane without necessarily having the correct normalization A?

It's also possible that the correct answer has the correct normalization and I've made some mistake.
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