Re: HW4, Question 1
Quote:
Originally Posted by rodrigo
I used the bound we derived in lecture 6: sum(i=0 to dvc, of N choose i ). This should yield a tighter bound on e as sum(i=0 to dvc of, N choose i ) <= (2N)^dvc
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I take it you used  since you are evaluating the growth function at  .
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