Re: Clarification on HW6Q8
yes, we don't need to:
1. compute delta for the output (because it doesn't need any of the operations, counted as operation in this certain task)
2. compute deltas for constants (because they're constants)
3. compute deltas for input (because they're just features (x), and delta is a derivative of the error with respect to s)
So for computing deltas you only need 3 operations.
