Thread: Q4) h(x) = ax
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Old 08-07-2012, 04:57 AM
itooam itooam is offline
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Default Q4) h(x) = ax

This question is similar to that in the lectures i.e.,

in the lecture H1 equals

h(x) = ax + b

Is this question different to the lecture in the respect we shouldn't add "b" (i.e., X0 the bias/intercept) when applying? Or should I treat the same?

My confusion is because in many papers etc a bias/intercept is assumed even if not specified i.e., h(x) = ax could be considered the same as h(x) = ax + b
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