Problem 1.1
I could not use Bayes' theorem to solve Problem 1.1 but I thought of an 'alternative' method which gave me the answer 2/3. I want to know if this method is right or not. It's as follows:
Since there are 2 black balls and 1 white ball left are choosing the first black ball, the chances that the second ball is black is 2/3 since there are 3 balls left.
Is this method right or not?
