Thread: Problem 1.9
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Old 10-23-2017, 07:23 AM
mygame182 mygame182 is offline
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Default Re: Problem 1.9

When 2^(-b) equal to the minimize of e^(-sa)U(s), i try to assume that 1-a=1/2-e, so that a = 1/2 + e, P[u>=a]=P[u>=1/2+e]

According to (b), P[u>=1/2+e] = P[u>=a] <= (e^(-sa)U(s))^N for any s , even if the minimize of e^(-sa)U(s) when s = ln(a / (1-a)).

Hence P[u>=1/2+e] <= 2^(-bN)
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