Thread: Q4) h(x) = ax
View Single Post
  #19  
Old 04-28-2013, 02:58 AM
Moobb Moobb is offline
Junior Member
 
Join Date: Apr 2013
Posts: 9
Default Re: Q4) h(x) = ax

I am lost at this.. The procedure I follow is as described above, but the answer doesn't seem right and from what I've read elsewhere it's a common mistake on this question.. any hints possible on what I might be missing? I am picking two points, getting the best hypothesis by minimising the squared error, repeating this a number of times and assuming the answer is the average value within these runs..
Reply With Quote