Thread: Problem 1.9
View Single Post
Old 10-22-2017, 04:19 AM
mygame182 mygame182 is offline
Junior Member
Join Date: Oct 2017
Posts: 2
Default Re: Problem 1.9

Originally Posted by RicLouRiv View Post
Ah, maybe it's because the inequality holds for any s, it must hold for the min.
Excuse me, I can understand your last reply, but confuse in this one.
More tips please.

When 2^(-b) is the minimize of e^(-sa)U(s), i find that 1-a = 1/2 + e (e means epsilon), so P[u>=a] = P[u>= 1/2 - e] , but not P[u>=1/2+e].
Reply With Quote