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Old 08-10-2014, 07:49 PM
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yaser yaser is offline
Join Date: Aug 2009
Location: Pasadena, California, USA
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Default Re: Question on HW2.1

Originally Posted by yusunchina View Post
P(#heads_min = i) = 1000 * P( one gets i intersect the others get >= i)
This formula assumes that the events "one gets i intersect the others get >= i" (with the "one" fixed at one coin at a time) are disjoint, otherwise this would be an over-count. These events are in fact overlapping. For instance, the case where all the coins get exactly i (which is admittedly an extremely unlikely event but chosen here as a simple illustration) would be counted in all 1000 cases, although it happens only "once."
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