
05-12-2016, 02:20 AM
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Junior Member
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Join Date: May 2016
Posts: 5
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Re: Noisy target - problem in understanding distribution
Quote:
Originally Posted by yaser
If we can express a function as a distribution, then considering only distributions will not exclude functions, hence there would be no loss in generality. The fact that we can indeed express a function  as a distribution  is based on using a "delta function" which allows distributions to put all the probability on a single value of  , thus making it effectively a function since  is uniquely determined by  .
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thank you yaser
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