It is not obvious at all, and for this reason I would recommend Problem 1.2 in the text in case anyone is having similar doubts.
The classification function:
is called linear because the weights appear 'linearly' in this formula. Now to see that this corresponds to what in highschool we learned as a line requires a little algebra.
First, the classification function is
not a line. The classification function is given by the formula above which assigns +1 to some regions of the space and 1 to others. What corresponds to the line is the
boundary between the region where the hypothesis is +1 and the region where the hypothesis is 1. It is the
separator that is a line.
Fix
. The boundary corresponds exactly to those points
for which
Lets consider the case in 2dim. Then
and
translates to
.
Rearrange a little and you have the following equation:
that must be satisfied by any point
that lies on the decision boundary. Thus, the decision boundary is indeed a line, and one can identify
.
Quote:
Originally Posted by scottedwards2000
The perceptron learning algo is very cool in its simplicity, but, although it was introduced in the course as sort of obviously linear, that was immediately apparen to me. Just wondering what made it obvious to others if it was. Is it the formula on page 6 (wsub1*xsub1 + wsub2*xsub2 + b = 0)? That seems similar to the old line equation of y=mx+b but not exactly same. However, after playing on paper with different choices of w's and b, I think I see that regardless of what values I choose for the weights and threshold that a line is formed. But how is that obvious theoretically that the shape is a line, without trying various values like i did?
