Thread: Q4) h(x) = ax
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Old 02-01-2013, 07:49 AM
melipone melipone is offline
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Join Date: Jan 2013
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Default Re: Q4) h(x) = ax

I thought it would simply be (y1/x1 + y2/x2)/2 to find an a that minimizes the mean square error on two points, no?
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