Thread: problem 1.2
View Single Post
  #4  
Old 09-20-2018, 03:42 AM
htlin's Avatar
htlin htlin is offline
NTU
 
Join Date: Aug 2009
Location: Taipei, Taiwan
Posts: 601
Default Re: problem 1.2

Quote:
Originally Posted by venkatesh-devale View Post
So as x2 = a*x1 + b classifies the set correctly which means for every x1, x2 on this line a*x1 + b - x2 = 0 hence w0*x0 + w1 * x1 + w2 * x2 = 0 for this line.

Considering these equations can we say that a = w1, b = w0 ? Is this correct now. Further what does the part 2 means what type of picture is expected?
If w_1 = 4, w_2 = 2, w_0 = 2 then the equation of the corresponding line is x_2 = -2 x_1 - 1. That is, a = -2, b = -1. The problem asks you to describe general procedure for any \mathbf{w} and then draw the corresponding line (along with which side to be positive) on the 2D plane for the specific \mathbf{w}. Hope this helps.
__________________
When one teaches, two learn.
Reply With Quote