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Old 04-19-2012, 08:57 AM
jcatanz jcatanz is offline
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Join Date: Apr 2012
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Default Re: When the growth function = 2^N

Quote:
Originally Posted by timhndrxn View Post
Please elaborate a little bit more in the text why this is an issue. It is crucial that the bound be polynomial. So why is 2^N bad, but N^9999 good?
Because exponential kills polynomial. I.e., for any real number a, in the limit N --> infinity N^a/2^N goes to zero.
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