Quote:
Originally Posted by yaser
The probability of getting 10 heads for one coin is (10 times) which is aprroximately .
Therefore, the probability of not getting 10 heads for one coin is approximately .
This means that the probability of not getting 10 heads for any of 1000 coins is this number multiplied by itself 1000 times, once for every coin. This probability is therefore .
This is approximately since . Numerically, .
Therefore, the probability of this not happening, namely that at least one coin of the 1000 coins will give 10 heads, is 1 minus that. This gives us the answer of approximately 0.63 or 63% that I mentioned in the lecture.

WOW!Thanks for the detailed explanation!It was over my head for a long time.