Re: Problem 1.9
Quick question on Part D...
I agree that s = ln(a / (1-a)) is the value of s that minimizes e^(-sa)U(s), where I'm using "a" to represent "alpha."
I think that, if you plug this value of s in, you get 2^(-b), where I'm using "b" to represent "beta."
So, 2^(-b) < e^(-sa)U(s), by definition of minimization.
Then, raising to the power of N, we get:
2^(-bN) < (e^(-sa)U(s))^N, but this inequality is the wrong way.
Any tips?
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