Thread: Q4) h(x) = ax
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Old 04-28-2013, 02:58 AM
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yaser yaser is offline
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Default Re: Q4) h(x) = ax

Quote:
Originally Posted by Moobb View Post
I am picking two points, getting the best hypothesis by minimising the squared error, repeating this a number of times and assuming the answer is the average value within these runs..
You are correct. This is the right procedure, where the answer you mention is {\bar g}(x) and the values you are averaging are g^{({\cal D})}(x).
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