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Old 05-22-2012, 08:23 AM
elkka elkka is offline
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Join Date: Apr 2012
Posts: 57
Default Re: code 3 in Octave qp optimizer

I have tweaked my trick, and now consider it perfectly legal. I think it mght be interesting to those who had the same problem.

So, first, I modified quadratic matrix H by adding to it a diagonal matrix with very small diagonal values. Specifically, I used 10^(-15). I passed otherwise unchanged problem to qp. The result was some \alpha_0, which I immediately used as an initial value for the original optimization problem (with original H).

The result. The first optimization converged in under 200 steps for N=10 in 100% cases. It converged in 99.99% cases for N=100. The latter optimization frequently took just 1 iteration, though occasionally I saw it take more than 100. It did converge in 100% cases. My E_in became consistently 0, and my b's differed by magnitude of the order less than 10^(-8) in 99.99% cases (and I don't believe the outlier influenced my averages all that much).

I believe the trick is legal, because all I do is I find a better initial value of \alpha, but then still solve the same optimization problem.
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