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magdon · #5 03-04-2018, 04:48 AM

For example, if you have 10 ways to dichotomize 4 points $x_1,\ldots,x_4$ and 8 ways to dichotomize another 4 points $x_5,\ldots,x_8$ , for each of the 10 ways for the first 4 points there are at most 8 ways to dichotomize the second 4 points (why?). Therefore, there are at most $10\times 8$ ways to dichotomize all 8 points.

Quote:

Originally Posted by pdsubraa

@Magdon - Can you explain us in detail.

That would help!

Thanks for your time!