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weiss 10-20-2012 08:43 AM

Definition "n choose k"
 
How do you define "n choose k" for k > n?

I learned in all my courses that this expression is not defined, but since I lost points in the questions 7 and 10, I think you are following another definition in this case.

yaser 10-20-2012 10:19 AM

Re: Definition "n choose k"
 
Quote:

Originally Posted by weiss (Post 6657)
How do you define "n choose k" for k > n?

It is defined as zero based on the combinatorial interpretation "the number of ways you can choose k objects from n distinct objects," which is none if k>n.


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