LFD Book Forum - Breaking Point

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- - Breaking Point (http://book.caltech.edu/bookforum/showthread.php?t=4585)

In general, can we say that the break point is the point that the hypothesis function h, changes from + to - or the opposite?

Re: Breaking Point

The breaking point does not act on one hypothesis, it acts on a whole hypothesis set. So your description may not work. Hope this helps.

Re: Breaking Point

Definition 2.3 on p. 45 of the LFD book says that "if NO data set of size k can be shattered by H, then k is the break point for H."

My understanding is that it should read: "if there is a data set of size k such that it can NOT be shattered by H, then k is the break point for H".

Is this correct?

Many thanks!

Re: Breaking Point

Quote:

Originally Posted by lfdid (Post 12288)

Apologies, "the break point" should be "a break point"

Re: Breaking Point

Quote:

Originally Posted by lfdid (Post 12288)

I don't think so. For the example of Positive rays (Page 43-44), the book also says:

Quote:

Notice that if we picked N points where some of the points coincided (which is allowed), we will get less than N + 1 dichotomies. This does not affect the value of mH(N) since it is defined based on the maximum number of dichotomies.

In the Positive intervals example, we have derived:

$m_{H}(N) = \frac{1}{2}N^{2} + \frac{1}{2}N + 1$

We observe that not all the value of k gets $m_{H}(k) < 2^{k}$ , indeed:

$m_{H}(k) = \frac{1}{2}k^{2} + \frac{1}{2}k + 1 = 2^{k} \Leftrightarrow k = 2$

This means that for some (not all) data set of size $k \leq 2$ , the hypothesis set H is able to shatter (in other words, be able to generate $2^{k}$ dichotomies). However, for any data set of size

, there is no way that the hypothesis set H is able to generate $2^{k}$ dichotomies.

For example, if

, the hypothesis set H is only able to generate 7 dichotomies (while $2^{3} = 8$ ). However, even when

, if the two points coincide (both have the same value of x), there is no way for H to generate $2^{2} = 4$ dichotomies on those points.

Re: Breaking Point

Quote:

Originally Posted by lfdid (Post 12288)

No, it shouldn't read so. For a break point, *no* data set of such a size can be shattered. So that is a very strong condition.

Re: Breaking Point

I was also looking for an answer to this question. Thanks for answering this. Much appreciated

Re: Breaking Point

:) Great info thanks