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Problem 1.8c
Not sure how the inequality in Problem 1.8c follows from parts a & b, but it is clear that the following inequality holds in 1.8c
P[(u - N*mu)^2 >= alpha] <= variance/(N*alpha) Any suggestions? |
Re: Problem 1.8c
Figured out the problem. I mistakenly thought the mean of u was N*mu.
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solution of 1.8C
1.8(c) solution
1.take [ (u1 - miu) + (u2 - miu) + ... + (un - miu) ] as a new random variable 2.its mean is 0, and variance is N * (variance of ui) do you got me? |
Re: solution of 1.8C
Quote:
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