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-   -   Hoeffding Inequality With Probability > 1? (http://book.caltech.edu/bookforum/showthread.php?t=4675)

henry2015 05-20-2016 11:29 PM

Hoeffding Inequality With Probability > 1?
 
Given that the inequality shows an upper bound of 2*e^(-2*N*(epsilon)^2).

If we have N = 10, and epsilon = 0.1, then we have

2*e^(-2*10*(0.1^2)) = 1.637461506.

So what does it mean? I thought we would never have a probability > 1.

ntvy95 05-21-2016 05:46 AM

Re: Hoeffding Inequality With Probability > 1?
 
Quote:

Originally Posted by henry2015 (Post 12363)
Given that the inequality shows an upper bound of 2*e^(-2*N*(epsilon)^2).

If we have N = 10, and epsilon = 0.1, then we have

2*e^(-2*10*(0.1^2)) = 1.637461506.

So what does it mean? I thought we would never have a probability > 1.

I think you can check out the first question in the Q&A section of Lecture 02.

henry2015 05-21-2016 12:03 PM

Re: Hoeffding Inequality With Probability > 1?
 
Quote:

Originally Posted by ntvy95 (Post 12366)
I think you can check out the first question in the Q&A section of Lecture 02.

Thanks for the link!


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